Cosθ= 1/2
Sinθ= 1/2
4Sin²θ - 3 = 0
3tan²θ=1
✓2 sec θ -2 = 0
Cosec θ = 2
3 sec ² θ - 4 = 0
Cosec² θ - 2 = 0
3 cot ² θ - 1 = 0
Solve the given trigonometric equation equation 0≰θ≤90°
- mskhanal
- Atheist. science lover . that's all
Cosθ= 1/2
Sinθ= 1/2
4Sin²θ - 3 = 0
3tan²θ=1
✓2 sec θ -2 = 0
Cosec θ = 2
3 sec ² θ - 4 = 0
Cosec² θ - 2 = 0
3 cot ² θ - 1 = 0
1 Comments
Sir 3rd question ma rationalise garnu bha ho
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